+ V6 R4 ?4 S; \8 Y1 c$ a int i,j,k,target_int_count=2;+ Y V6 P2 o ~8 G' C, U
char ch[2]; 1 m! b- \, e! c- t 6 r: s' w& Z/ x, _$ d' d2 e* w9 Z% [% [% k. P
0 F1 ]6 a$ k& f* Z$ T6 N upp_interrupt_count = 0;# S6 I/ |5 w# A) i
upp_error_count = 0; 9 O# O- q/ y1 P( Y: f z5 Y; C6 x/ G" P UARTPuts("\tResetting uPP buffers...\r\n",-2); ' g! q: y6 _5 k' u // Initialize data buffers" D% d: [$ O% P
for (i = 0; i < upp_frame_size; i++) . H; x% k* q+ O w& K# Q {2 v% K$ n; L9 L, ~
upp_buffer_b =i;) L, c& B9 @. E2 ^+ o. f
upp_buffer_a = 0xDEAD;5 b- W7 k! }4 ~
}' S4 P) t8 ^0 l* X% r" ^& s% p
% Q# v9 i2 u1 ^1 G //for(i=0;i<1024;i++): B6 N: f: ]& K9 u F
// temp=0; $ d% [! C4 N/ J, j/ R( m( M0 F; f3 M1 h/ [; I- D
//UPPReset();/ D3 c9 _5 c ~& M: x/ @! [: r
/*启动UPP DMA传输*/* a @* C% ?* H$ L. J
UARTPuts("upp_prog_dma_i\n",-2);8 Q. E$ m! s$ B: C9 }9 j6 P8 d
upp_reg_hdl->UPID0 = (Uint32)upp_buffer_a;3 d/ v/ v/ a9 P: H' H
upp_reg_hdl->UPID1 = ((Uint32)upp_line_count << 16) | (Uint32)upp_line_size*sizeof(Int16); 4 _# ]2 C0 e$ U& S7 W upp_reg_hdl->UPID2 = (Uint32)upp_line_offset*sizeof(Int16);1 W4 g5 H. C$ u1 J, h8 m. s
* T! q2 D0 e$ o1 ~
UARTPuts("upp_prog_dma_i\n",-2);2 o$ y, h% Y6 o, M* b, ~) ]
upp_reg_hdl->UPQD0 = (Uint32)upp_buffer_b;9 c& ~1 @- N7 t/ R+ P
upp_reg_hdl->UPQD1 = ((Uint32)upp_line_count << 16) | (Uint32)upp_line_size*sizeof(Int16); 9 C7 N; @6 X' ] upp_reg_hdl->UPQD2 = (Uint32)upp_line_offset*sizeof(Int16);/ m7 E7 C: B$ y; R! H
8 a, x8 m4 u, H( D( U/ _* U& @2 W
/*等待UPP传输完毕*/4 S( x( k7 T( Z2 D5 f9 u+ B+ f
//i=0;0 g$ ~/ X- R7 d8 \+ ?
//j=0;2 i. i% W: b# p2 x
while (upp_interrupt_count < target_int_count && upp_error_count == 0) 5 |& V( Q5 A, O& O/ o {( G4 D# l# i/ ]' ? J* E" e7 R
/* 测试UPP传输的同时操作普通DDR数据/ f( M( {/ y" l* q3 R2 V9 z- e3 I
temp=i;1 |4 B! Q, m2 j
i++; 0 C" Y* F* ]) s) F3 }2 A' x6 y if(i==1024) ! @: l8 M; i0 n/ }- B. o4 w { 4 L, B0 H" E/ U/ X1 ?6 u i=0; ) W6 {" f7 v H j' v; Z+ y8 n j++; ! E# K7 X+ d4 m' z# G8 a }8 p3 P' Q. p" [9 z
*/( V, |5 n+ j' Z6 E
( ?( r: A- ~* M9 C& h
asm(" nop"); * i2 _* `6 p w% Q! c4 c # x( F) u% e( x T //UARTprintf( "upp_interrupt_count=%d\n",upp_interrupt_count);6 ~7 H3 I y: G7 S% b* Z m
} 1 |, [# R' v h+ h; H9 Q* R( L% T9 P% h% p" ^
/*检查UPP传输的数据是否正确 (loopback modes only)*/ 1 y8 p1 y$ ^4 \) C6 s! h. l //UARTprintf( "i=%d\n",i); $ ~% t% |' B& ~- L //UARTprintf( "j=%d\n",j);5 \) [* ~( c/ D* ^% O- b
UARTPuts("Data mismatch in buffers.\n",-2);& U7 q8 y% E% e. V2 i2 h- R/ O* y
if (upp_interrupt_count == 2 && upp_error_count == 0) * ?* H4 K) d1 _. }; Q+ H v, F; c2 @ { 3 V4 p* |! p6 ^/ L for (i = 0; i<upp_frame_size; i++) 6 q v/ i5 n9 \7 ], S. J- K9 E {# V* k2 |# D8 W5 i3 R1 P7 C' a
if (upp_buffer_a != upp_buffer_b)# E: }- u8 G; w+ F* U) a1 S& P+ Z& C8 z5 u
{: }; x! M: I8 n* I. D& c+ l8 R
upp_error_count++; $ \* G: |: h7 ^' q" p# ^- }8 S } ! |: H; B+ _! S E } / e: s% x% Q/ k9 N- M) c9 w. k6 b }2 k4 j' p0 k3 y& l" N8 a, [; S
5 M* o w' {- P3 _
/* 报告通信结果*/6 O2 G, n9 n% ]* N
if(upp_error_count != 0) 1 O. u+ T4 {5 i/ t UARTprintf( "upp_error_count=%d\n",upp_error_count); + u3 y# E6 S7 ~1 F# f else; W$ q# V d4 g G# z: y5 c
UARTPuts("uPP transfers complete!\n",-2); : |$ x- Q/ D0 _2 {# `) L3 U" H 3 {+ a: `5 ]% n6 |0 {0 O- I* a UARTPuts("Do you want to print all the data?(y/n) ",-2); ) f: K/ T# n( i, e# z3 Q UARTGets(ch,2); - ]" B X, O2 `9 Y9 p UARTPuts("\n", -2);) j1 ~; m8 i( J) s- _
* c; x0 J! {1 m9 M+ P. ]- q if(ch[0] == 'y') C Z3 n. w' W {" h, c' I. y/ y9 j3 b
/*打印全部读到的数据*/ }8 d0 o# n; m; W for(i=0; i<upp_frame_size; ) H2 n- H N7 |4 m1 M+ ^ { - ?; ^% X) l* i t4 m/ K for(j=0; j<5; j++)( Q9 M2 E5 b7 Z! b
{ / q6 \' Z* c; M# m8 w/ P" o UARTprintf("upp_buffer_a[%d]=%d ",i,upp_buffer_a);2 b- j: A: b1 J9 N4 g
i++; ! U! Z |9 ?: F7 J% t //if(i >= 4096) 0 O! k9 D2 e' `+ F c; | // break; + w+ {; T( e& X/ u8 s0 r4 I: X ! B; n @& g# q' p2 y }6 `, H8 _ S9 D* f. I6 H9 L
UARTPuts("\n",-2);+ l. t+ ~- K5 z/ D. m
} . q% \( @( H1 I9 _) T- F! z) | } * y8 y& B% j7 E7 K6 {* `" |2 y 2 l: J" J8 _3 t& `& L% ~}# i \- {: q7 m, Y
- G+ i: [8 N, f2 U& Y" B / y9 ]# L5 ^' E5 `$ G作者: tulipyyf 时间: 2014-12-22 16:08
追加说明:任务是空闲任务,因此没有做循环。 + O7 s9 a) g' c作者: Lewis 时间: 2014-12-24 18:06
多次执行是没问题的,最好不要用空闲任务,优先级太低。 , D6 q; I5 R' m